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4x^2-1.9x-1.9=0
a = 4; b = -1.9; c = -1.9;
Δ = b2-4ac
Δ = -1.92-4·4·(-1.9)
Δ = 34.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.9)-\sqrt{34.01}}{2*4}=\frac{1.9-\sqrt{34.01}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.9)+\sqrt{34.01}}{2*4}=\frac{1.9+\sqrt{34.01}}{8} $
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